Q16 of 31 Page 65

The length of each of two parallel chord is 16 cm. If the length of the radius of the circle is 10 cm, then the distance between two chords is


Let Parallel Chords are AB and CD. OE and OF are perpendicular bisector of AB and CD respectively.


Given, OB = OA = OD = OC = 10cm, AB = CD = 16cm


⇒ DF


⇒ DF


⇒ DF = 8cm


⇒ EB


⇒ EB


⇒ EB = 8cm


In AOE


⇒ OA2 = AE2 + OE2


⇒ OE2 = OA2-AE2


⇒ OE2 = 102-82


⇒ OE2 = 100-64


⇒ OE2 = 36


⇒ OE = 6cm


As we can see from the previous question both the triangles are congruent.


So, OE = OF


Hence Distance between parallel lines = OE + OF = 6 + 6 = 12cm

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