In a triangle ABC, ∠A = 110° and AB = AC. Find ∠B and ∠C.
In the given ∆ABC,
∠A = 110° and AB = AC
⇒ ∠B = ∠C {angles opposite to equal sides are equal}
Also, sum of all the angles of a triangle is 180°.
⇒ ∠A + ∠B + ∠C = 180°
⇒ 2∠B = 180° - 110°
⇒ 2∠B = 70°
⇒ ∠B = ∠C = 35°
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