In a right angled triangle, if one of the other two angles is 35°, find the remaining angle.
Given:
Let ∠A = 35° and ∠B = 90° (right angle)

As we know, using theorem (1), in any triangle, sum of the three interior angles is 180 °.
So,
∠A + ∠B + ∠ C = 180°
⇒ 35° + 90° + ∠ C = 180°
⇒ ∠ C = 180° - 35° - 90°
⇒ ∠ C = 55°
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