Q3 of 34 Page 113

If the vertex angle of an isosceles triangle is 50°, find the other angles.

Given: vertex angle

let A = 55°


in an isosceles triangle opposite angles of opposite sides are equal.


Hence,


Let B = C = x



As we know, using theorem (1), in any triangle, sum of the three interior angles is 180 °.


So,


A + B + C = 180°


50° + x + x = 180°


2x = 180° - 50°


2x = 130°


x = 65°


So, B = C = 65°.


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