If the vertex angle of an isosceles triangle is 50°, find the other angles.
Given: vertex angle
let ∠A = 55°
in an isosceles triangle opposite angles of opposite sides are equal.
Hence,
Let ∠B = ∠ C = x

As we know, using theorem (1), in any triangle, sum of the three interior angles is 180 °.
So,
∠A + ∠B + ∠ C = 180°
⇒ 50° + x + x = 180°
⇒ 2x = 180° - 50°
⇒ 2x = 130°
⇒ x = 65°
So, ∠B = ∠ C = 65°.
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