In a triangle ABC, if 2∠A = 3∠B = 6∠C, determine ∠a, ∠B and ∠C.
In a triangle ABC, it is given that
2∠A = 3∠B = 6∠C
⇒ 2∠A = 6∠C
⇒ ∠A = 3∠C
Similarly,3∠B = 6∠C
⇒ ∠B = 2∠C
We know that the sum of the angles of a triangle is 180°.
⇒ ∠A + ∠B + ∠C = 180°
⇒ 3∠C + 2∠C + ∠C = 180°
⇒ 6∠C = 180°
⇒ ∠C = 30°
So, ∠A = 3× ∠C = 90°
∠B = 2× ∠C = 60°
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