Q3 of 59 Page 152

Construct a triangle PQR in which PQ = 4 cm, QR = 4.5 cm and Q = 60°.

Step1: construct segment PQ of 4 cm



Step2: construct a line at 60° from point Q using a protractor



Step3: take distance 4.5 cm in compass and keep the needle of the compass on point Q and mark an arc intersecting the line drawn in Step2. Mark the intersection point as R



Step4: join PR and ΔPQR is ready



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