Construct an isosceles triangle whose altitude is 4.5 cm and vertex angle is 70°.
Here, we are given with altitude of triangle, that is, 4.5 cm and vertex angle equals to 70°. Let us construct an isosceles triangle using the following steps of construction.
Steps of construction:
1. Draw a line segment XY using a ruler of any length.
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2. Take a point M on line XY and draw a perpendicular line MP such that MP ⊥ XY; use protractor to measure the angle 90°.

3. Now, with M as centre draw a circle or semicircle or an arc of radius 4.5 cm cutting MP at A using a compass and a ruler.
4. 
on XY such that, ∠MAB = 35°
and ∠MAC = 35°
. Measure the angles using a protractor.

Thus, ABC is the required isosceles triangle.
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