Construct a triangle PQR in which PQ = 5.4 cm, QR = 5.5 cm and ∠PQR = 55°.
We have been given two sides and one angle of triangle PQR.
Steps of construction for this case would be:
1. Draw a line segment sufficiently long using a ruler.
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2. Locate points Q and R such that QR = 5.5 cm, on the line segment so formed in step 1 and you can even erase the unnecessary line.

3. At Q, construct a line segment QX, sufficiently large, such that ∠XQR = 55°; use protractor to measure the angle 55°.

4. With Q as centre and radius 5.4 cm, draw a circle or semicircle or an arc cutting the line segment QX at P using a compass and a protractor.

5. Join PR.

Thus, PQR is the required triangle.
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