Construct a triangle ABC in which BC = 4.5 cm, ∠B = 35° and the difference between the other two sides is 2.8 cm.

Step1: draw segment BC of length 4.5 cm which is base

Step2: draw a ray at 30° from point B

Step3: using a compass or scale mark a point on the ray constructed in step2 at a distance of 2.8 cm(difference is given) from point B. mark that point as D i.e. BD = 2.8 cm

Step4: join points C and D to make segment CD

now we have to draw perpendicular bisector of CD

Step5: take any distance approximately by observation in compass greater than half of CD. Keep the needle of the compass on point C and mark arcs above and below CD and keeping the same distance in compass keep the needle on point D and cut the arcs as shown and join both the intersected arcs. Thus we have drawn the perpendicular bisector of the CD. Mark the intersection point of the perpendicular bisector of CD and ray drawn in step2 as point A

Step6: join AC and ΔABC is ready