In the adjacent sum, A, B, C are consecutive digits. In the third row, A, B, C appear in some order. Find A, B, C.

Given A, B and C are consecutive numbers
Let A = x, then B = x + 1 and C = x + 2
C + A = x + x + 2 = 2x +2
B + B = x + 1 + x + 1 = 2x +2
A + C = 2x+2
Considering A, B and C at one`s place respectively
(a) C + A + A = 2x + 2 + x = 3x + 2 = 12 or 22
∴
which are not possible solutions
(b) C + A + B = 2x +2 + x + 1 = 3x +3 = 12 or 22
⇒ ![]()
But
is not a possible solution
So x = 3
⇒ A = 3 and B = 4 and C = 5
We can verify the solution by putting the values in the question

(Here order is A C B)
Couldn't generate an explanation.
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