Find the least natural number larger than 100 which leave the remainder 12 when divided by 19.
Since we have to find a number greater than 100
So first we will find the quotient and remainder for 100 when divided by 19
Here s = 100
We know If s → (q, r) denotes the quotient q and r denotes the remainder r
Then s = (b × q) + r where s and b > 0 and 0 ≤ r < b
When s is divided by 19 then
100 = 19 × 5 + 5
Here the quotient = 5 and r = 5
But the remainder has to be 12 so the 5+ 7 = 12
So the least natural number 107 (100 +7)
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