A number is 56 greater than the average of its third, quarter and one-twelfth. Find it.

Let the number is = x

Its third, quarter and one-twelfth are taken, and respectively.

According to the question;

We multiplying by 3 in both the sides and we get

Take the L.C.M. of 3, 4 and 12 and multiplying both the side

we get

4x + 3x + x + 2016 = 36x

36x–8x = 2016

28x = 2016