What number is that of which the third part exceeds the fifth part by 4?
Let, the number be = x
According to the given problem
The third part of the number ![]()
Also,
Fifth part of the number ![]()
Now, Third part exceeds the fifth part by 4
![]()
Find the LCM of 3 and 5 = 3 × 5 = 15
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After cancellation
x = 2 × 15
x = 30
Therefore,
Required number is 30
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