Suppose a girl throws a die. If she gets 1 or 2 she tosses a coin three times and notes the number of tails. If she gets 3,4,5or 6, she tosses a coin once and notes whether a ‘head’ or ‘tail’ is obtained. If she obtained exactly one ‘tail’, what is the probability that she threw 3,4,5 or 6 with the ride ?
Let A be the event that girl will get 1 or 2
P(A) =
= ![]()
Let B be the event that girl will get 3, 4, 5 or 6
P(B) =
= ![]()
P(T/A) = Probability of exactly one till given she will get 1 or 2 = ![]()
P(T/B) = Probability of exactly one till given she will get 3, 4, 5 or 6
= ![]()



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Hence the probability that she threw 3,4,5 or 6 with the ride is
.
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