Two numbers are selected at random (without replacement) from the first five positive integers. Let X denote the larger of the two numbers obtained. Find the mean and variance of X.
X can take values as 2,3,4,5 such that P(X – 2) = probability that the larger of two number 2 = probability of getting 1 in first selection and 2 in second selection getting 2 in first selection and 1 in second selection.
∴
P(X – 2) = ![]()
Similarly,
∴
P(X – 3) = ![]()
∴
P(X – 4) = ![]()
∴
P(X – 5) = ![]()

E(X) = 2
E(
) = 4![]()
Therefore, V(X) = E(X) – E(
)
= 17 – 16
= 1.
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.


