Evaluate 
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OR
Evaluate
.
Let I = ![]()
Here, we express the denominator in terms (sin x – cos x) which is the integration of numerator.
Clearly, ![]()
![]()
Therefore,
becomes,


Let, sin x – cos x = t.
Then, d(sin x – cos x) = dt
(cos x + sin x)dx = dt.
Also x = 0
t = sin0 – cos0 = – 1 and x = ![]()
![]()
∴ 



OR
(let)
When
; a = 1, b = 3
![]()
![]()
![]()
![]()





As
∴ ![]()

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Couldn't generate an explanation.
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