Q1 of 26 Page 1

Evaluate:

Let,



Then,



cosθ =cos(90+37 )


Therefore, θ = (90+37)°



= 2sinθ.cosθ


= 2 sin(90+ 37).cos(90+ 37)


as cos(90 +θ)= – cos(θ) Because θ lies in second quadrant


= – 2 sin(37).cos(37)




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