Using integration, find the area bounded by the tangent to the curve 4y = x2 at the point (2, 1) and the lines whose equations are x =2y and x = 3y–3.
Given Data:
Parabolic Curve 4y = x2
Equation of lines: x =2y and x = 3y–3
Calculation:
Now differentiating the curve 4y = x2 w.r.t x
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At point (2, 1),
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Equation of a tangent passing through (2, 1)
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y = x – 1
Plot of all the equations are given in figure
The area bound by the three lines can be found as
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A = 1 square units
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