If 2 is a root of the equation x2 + kx + 12 = 0 and the equation x2 + kx + q = 0 has equal roots, find the value of q.
2 is a root of the equation, x2 + kx + 12 = 0.
Therefore, 2 must satisfy the equation
⇒ 22 + k(2) + 12 = 0
⇒ 4 + 2k + 12 = 0
⇒ k = –8
Now, x2 + kx + q = 0 has equal roots.
Concept used:
If a quadratic equation ax2 + bx + c = 0 has equal root, then
D = b2 – 4ac = 0
Now, for second equation
a = 1
b = k = –8
c = q
D = b2 – 4ac
⇒ 0 = (–8)2 – 4(1)(q)
⇒ 64 = –4q
⇒ q = 16
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