The perimeters of the ends of the frustum of a cone are 207.24 cm and 169.56 cm. If the height of the frustum be 8 cm, find the whole surface area of the frustum. (Use π= 3.14)
Let r, R be radii of frustum (R>r) and h be the height of frustum.
Formula
Total surface area of frustum = π(R2 + r2 + (R + r)l)
Where, l is the slant height of frustum.
And ![]()
Perimeter of circular cylinder = 2πr
Given
Perimeter of bigger end = 207.24 cm
⇒ 2πR = 207.24
⇒ 2 × 3.14 × R = 207.24
⇒ R = 33 cm
Perimeter of smaller end = 169.56 cm
⇒ 2πr = 169.56
⇒ r = 27 cm
Height, h = 8 cm
Slant height, ![]()
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Putting values in formula, we get
Total surface area = π(332 + 272 + (33 + 27)10)
= 3.14(1089 + 729 + 600)
= 7592.53 cm2
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.
