Show that the matrix
satisfies the equation A3 – 4A2 + A = 0.
Given: ![]()
To show that ![]()
Now, we will find the matrix for A2, we get
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[as cij = ai1b1j + ai2b2j + … + ainbnj]
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Now, we will find the matrix for A3, we get
![]()
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So,
![]()
Substitute corresponding values from eqn(i) and (ii), we get
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[as rij = aij + bij + cij]
![]()
Therefore,![]()
Hence matrix A satisfies the given equation.
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