If
then find A2 – 5A – 14I. Hence, obtain A3.
Given
.
We need to find A2 – 5A – 14I.
We know A2 = A × A.
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Now, we evaluate –5A = –5 × A.
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Finally, matrix –14I = –14 × I.
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The given expression is A2 – 5A – 14I.
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On multiplying both sides with matrix A, we get
A (A2 – 5A – 14I) = O
⇒ A3 – 5A2 – 14(A × I) = O
⇒ A3 – 5A2 – 14A = O
⇒ A3 = 5A2 + 14A
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Thus,
and
.
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