If
find A2 – 5A – 14I.
Given: ![]()
I is identity matrix so ![]()
To find ![]()
Now, we will find the matrix for A2, we get
![]()
![]()
[as cij = ai1b1j + ai2b2j + … + ainbnj]
![]()
![]()
Now, we will find the matrix for 5A, we get
![]()
![]()
![]()
So,
![]()
Substitute corresponding values from eqn(i) and (ii), we get
![]()
![]()
[as rij = aij + bij + cij]
![]()
Therefore,![]()
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