find the equation of the ellipse in the following cases:
eccentricity
and major axis = 12
Given that we need to find the equation of the ellipse whose eccentricity is
and the major axis is 12.
Let us assume the equation of the ellipse as
(a2>b2).

We know that eccentricity(e) = ![]()
⇒ ![]()
⇒ ![]()
⇒ ![]()
⇒ ![]()
We know that length of ,ajor axis is 2a.
⇒ 2a = 12
⇒ a = 6
⇒ a2 = 36
⇒ ![]()
⇒ b2 = 27
The equation of the ellipse is
⇒ ![]()
⇒ ![]()
⇒ 3x2 + 4y2 = 108
∴ The equation of the ellipse is 3x2 + 4y2 = 108.
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