For the ellipse 12x2 + 4y2 + 24x – 16y + 25 = 0
Given that we need to find the centre, lengths of axes, eccentricity and foci of the ellipse 12x2 + 4y2 + 24x - 16y + 25 = 0.

⇒ 12x2 + 4y2 + 24x - 16y + 25 = 0
⇒ 12(x2 + 2x + 1) + 4(y2 - 4y + 4) - 3 = 0
⇒ 12(x + 1)2 + 4(y - 2)2 = 3
⇒ ![]()
⇒ ![]()
Comparing with the standard form ![]()
⇒ Centre = (p,q) = (1, - 2)
Here b2>a2
⇒ eccentricity(e) = ![]()
⇒ 
⇒ 
⇒ ![]()
Length of the major axis 2b = ![]()
Length of the minor axis 2a =
= 1
∴ The correct option is D
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