find the equation of the ellipse in the following cases:
Foci (± 3, 0), a = 4
Given that we need to find the equation of the ellipse whose foci are (±3,0) and a = 4.
Let us assume the equation of the ellipse as
(a2>b2).

⇒ a = 4
⇒ a2 = 16
We know that foci = (±ae,0)
⇒ ae = 3
⇒ 4e = 3
⇒ ![]()
We know that eccentricity ![]()
⇒ ![]()
⇒ ![]()
⇒ ![]()
⇒ b2 = 7
The equation of the ellipse is
⇒ ![]()
⇒ ![]()
⇒ 7x2 + 16y2 = 112
∴ The equation of the ellipse is 7x2 + 16y2 = 112.
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