Find the centre, the lengths of the axes, eccentricity, foci of the following ellipse:
x2 + 2y2 - 2x + 12y + 10 = 0
Given that we need to find the centre, lengths of axes, eccentricity and foci of the ellipse x2 + 2y2 - 2x + 12y + 10 = 0.

⇒ x2 + 2y2 - 2x + 12y + 10 = 0
⇒ (x2 - 2x + 1) + 2(y2 + 6y + 9) - 9 = 0
⇒ (x - 1)2 + 2(y + 3)2 = 9
⇒ ![]()
⇒ ![]()
Comparing with the standard form ![]()
⇒ Centre = (p,q) = (1, - 3)
Here a2>b2
⇒ eccentricity(e) = ![]()
⇒ ![]()
⇒ ![]()
⇒ ![]()
⇒ ![]()
Length of the major axis 2a = 2(3) = 6
Length of the minor axis 2b =
= 3![]()
⇒ Foci = (p±ae,q)
⇒ Foci = 
⇒ Foci = ![]()
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