Q30 of 318 Page 29

Evaluate the following limits:


We know,



cos2x = 1 – 2sin2x


⇒ 2sin2x = 1 – cos2x






Dividing numerator and denominator by x2:




We know,



Therefore,







Put 3x = y & 5x = t:



Formula used:



Therefore,






Hence, the value of


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