Show that 
To Prove: ![]()
We have L.H.S ![]()
Rationalizing the numerator, we get,


Taking x as common from both numerator and denominator,


![]()
Therefore, ![]()
Now , Take R.H.S ![]()





Now
then
Therefore, R.H.S = 0
So, L.H.S ≠ R.H.S
Hence, ![]()
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