Evaluate the following limits:

As we need to find ![]()
We can directly find the limiting value of a function by putting the value of the variable at which the limiting value is asked if it does not take any indeterminate form (0/0 or ∞/∞ or ∞-∞, .. etc.)
Let Z = ![]()
∴ We need to take steps to remove this form so that we can get a finite value.
TIP: Most of the problems of logarithmic and exponential limits are solved using the formula
and ![]()
It also involves a trigonometric term, so there is a possibility of application of Sandwich theorem- ![]()
As Z = ![]()
As, 1-cos x = 2sin2(x/2)
∴ Z = ![]()
⇒ Z = ![]()
To get the desired form to apply the formula we need to divide numerator and denominator by x2.
⇒ Z = 
Using algebra of limits, we have-
Z = 
Use the formula:
and ![]()
∴ Z = ![]()
⇒ Z = 2 log 2
Hence,
![]()
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