Q3 of 30 Page 6

Find the slope of the tangent to the curve y = x3 + 3x2 – 7 at the point whose x-coordinate is 4.

y = x3 + 3x2 – 7


Slope of tangent at a point ‘p’ is given by


Let us first find


Differentiate given y with respect to x



Now we have to find slope at x = 4


Hence put x = 4





Hence slope of tangent to the given curve at x = 4 is 72


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