Find the point at which the tangent to the curve has its slope .

Let the point be (a, b) at which the slope of tangent is

Slope of tangent is given by

Slope of tangent at (a, b) is given as which means

Differentiate y with respect to x

Put (a, b) in

Square both sides

⇒ 4a – 3 = 9

⇒ 4a = 12

⇒ a = 3

As (a, b) lies on the cure hence it satisfies the curve equation

Put (a, b) in curve equation

⇒ b = √9

⇒ b = 3

Hence the point at which tangent to given curve having slope is (3, 3)