Q2 of 30 Page 13

From a pack of 52 cards, two are drawn one without replacement. Find the probability that both of them are kings.

Total number of all favorable cases is n(S) = 52


Let A be the event that first card drawn is a king. There are four kings in the pack. Hence, the probability of the first card is a king is



Let B be the event that second card is also king without replacement. Then there are 3 kings left in the pack as the cards are not replaced. Therefore, the probability of the second card is also king is



Then the probability of getting two kings without replacement is





The probability that both of them are kings is

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