Let
and a = 4, b = –2.
Show that:
A(BC) = (AB)C
To prove: A(BC) = (AB)C
LHS = A(BC) = ![]()
⇒ LHS = ![]()
⇒ LHS = ![]()
⇒ LHS = ![]()
RHS = (AB)C = ![]()
Performing matrix multiplication as done for LHS
⇒ RHS = ![]()
⇒ RHS = ![]()
Clearly LHS = RHS = ![]()
∴ A(BC) = (AB)C …proved
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