Let
and a = 4, b = –2.
Show that:
a(C – A) = aC –aA
To prove: a(C – A) = aC –aA
As, LHS = a(C – A) = 4![]()
⇒ LHS = 4![]()
RHS = aC – aA = ![]()
⇒ aC – aA = ![]()
Clearly LHS = RHS = ![]()
Hence,
a(C – A) = aC –aA …proved
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