Let and a = 4, b = –2.

Show that:

(A – B)C = AC – BC

c) To prove: (A – B)C = AC – BC

As, LHS = (A – B)C

Putting the values of A,B and C and multiplying by rule of matrix multiplication.

LHS =

⇒ LHS =

RHS = AC – BC =

⇒ RHS =

Clearly, LHS = RHS =

Hence (A-B)C = AC - BC…proved