Find inverse, by elementary row operations (if possible), of the following matrices.

Let A = ![]()
To apply elementary row transformations we write:
A = IA where I is the identity matrix
We proceed with operations in such a way that LHS becomes I and the transformations in I give us a new matrix such that
I = XA
And this X is called inverse of A = A-1
So we have:
![]()
Applying R2→ R2 + 5R1
⇒ ![]()
Applying R2→ (1/22)R2
⇒ ![]()
Applying R1→ R1 – 3R2
⇒ 
As we got Identity matrix in LHS.
∴ A-1 = 
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