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Q60 of 107 Page 107

If y^x = e^y–x, prove that

Given: y^x = e^{y – x}

Taking log on both the sides, we get

log y^x = log e^{y – x}

⇒ x logy = y – x

…(i)

On differentiating both the sides with respect to x, we get

[using (i)]

Hence Proved

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