Q80 of 107 Page 107

If prove that

We have, xm.yn = (x+y) m+n


Taking log on both sides, we get


log (xm.yn) = log (x+y) m+n


⇒ m log x + n log y = (m+n) log (x+y)


Differentiating both sides w.r.t x, we get



⇒


⇒


⇒


⇒


⇒


⇒


Hence proved.


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