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5. Continuity And Differentiability
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Q82 of 107 Page 107

Find

We have,


Putting xtanx = u and


u = xtanx


Taking log on both sides, we get


log u = tanx log x


Differentiating w.r.t x, we get


⇒


⇒


⇒ (i)


Now,


⇒


Differentiating w.r.t x, we get


⇒


⇒ (ii)


Now, y = u + v


⇒


On substituting the values of from (i) and (ii),we get


⇒


⇒


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5. Continuity And Differentiability
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