Q85 of 107 Page 107

The set of points where the function f given by f(x) = |2x – 1| sinx differentiable is

We have, f(x) = |2x – 1| sinx


Now, 2x-1 = 0


⇒


Now we will check the differentiability of f(x) at 1/2.



=


= (∵ f(x) = |2x – 1| sinx)


=


=


=



=


= (∵ f(x) = |2x – 1| sinx)


=


=


=


∴


Hence, f(x) is not differentiable at

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