Q3 of 26 Page 1

At a place, the horizontal component of earth’s magnetic field is B and angle of dip is 60o. What is the value of horizontal component of the earth’s magnetic field at equator?

Let, Total magnetic field is B and,


BH be the horizontal component of the magnetic field.



At given place, Horizontal component of magnetic field is given by,


BH = B cos60


⇒


∴ B = 2BH


At equator dip angle = 00


∴ B’H = I cos0 = I = 2BH


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