Q3 of 66 Page 7

If A(-6, 7) and B(-1, -5) are two given points then the distance 2AB is(CBSE 2011)

⇒


⇒ Distance AB =


=


= √(25 + 144 )


= √(169 )


= 13


⇒ Distance 2AB = 2×13


= 26 units.


Therefore the distance 2AB is 26 units.

More from this chapter

All 66 →
1

The point P which divides the line segment joining the points A(2, -5) and B(5, 2) in the ratio 2 : 3 lies in the quadrant. (CBSE 2011)

 2

The area of ΔABC with vertices A(a, 0), O(0, 0) and B(0, b) in square units is(CBSE 2011)

 4

The distance of the point (-3,4) from x- axis is (CBSE 2012)

 5

In the given figure P(5, -3) and Q(3, y) are the points of trisection of the line segment joining A(7, -2) and B(1, -5). Then, y equals

(CBSE 2012)