In Fig. 8, the vertices of ∆ABC are A(4, 6), B(1, 5) and C(7, 2). A line segment DE is drawn to intersect the sides AB and AC at D and E respectively such that
. Calculate the area of ∆ADE and compare it with area of ∆ABC.
(CBSE 2016)
Given three coordinates A(4, 6) B(1, 5) and C(7, 2)
D divides AB in 1 : 3 and E divides AC in ratio 1 : 3
we know that the coordinates of the points P(x, y) which divides the line segment joining the points A(x1, y1) and B(x2, y2), internally in the ratio m : n are
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So


As we know area of triangle formed by three points (x1, y1), (x2, y2) and (x3, y3)
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and


Hence, Ratio is 104: 15
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