Q6 of 26 Page 1

Calculate the freezing point of a solution containing 60 g of glucose (Molar mass = 180 g mol–1) in 250 g of water.

(Kf of water = 1.86 K kg mol–1)

We know

ΔT f= k f × m


Where ΔTf is the depression in the freezing point


Kf freezing constant for water


m is molality


The molality(m) of a given solution of glucose:



M=1.33 mol kg-1


Putting the values in the equation, we get


ΔTf= 1.86 × 1.33K


ΔT f= 2.4738K


ΔT f = T f × 2.4738K


Δt(solution) = t(solvent) – ΔTf


ΔT f= Tf0 2.4738K


= 273.15 - 2.4738K


= 270.65K


More from this chapter

All 26 →
4

Out of chlorobenzene and benzyl chloride, which one gets easily hydrolysed by aqueous NaOH and why ?

 5

Write the IUPAC name of following:

 7

For the reaction

2N2O5(g) → 4NO2(g) + O2(g) ,


the rate of formation of NO2(g) is 2.8×10-3Ms-1 . Calculate the rate of disappearance of N2O5 (g) .

 8

Among the hydrides of Group-15 elements, which have the

(a) Lowest boiling point ?


(b) Maximum basic character ?


(c) Highest bond angle ?


(d) Maximum reducing character?