Q7 of 26 Page 1

For the reaction

2N2O5(g) → 4NO2(g) + O2(g) ,


the rate of formation of NO2(g) is 2.8×10-3Ms-1 . Calculate the rate of disappearance of N2O5 (g) .

2N2O5(g) → 4NO2(g) + O2(g)

The rate of the reaction is given by


Rate=1/2 {-Δ[N2O5]/ Δt}


Or


{-Δ[N2O5]/ Δt} =1/2{[NO2 / Δt]}


= 2.8×10-3


× = =



The rate of disappearance = = 1.4 ×10-3M/sec


So, the rate of disappearance of N2O5 would be half of rate of production of NO2. So the rate of disappearance of N2O5 is 1.4 ×10-3M/sec


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