Q9 of 33 Page 6

Find the equation of the normal to the curve ay2 = x3 at the point (am2, am3). (CBSE 2012)

finding the slope of the tangent by differentiating the curve




m(tangent) at (am2, am3) is


normal is perpendicular to tangent so, m1m2 = – 1


m(normal) at (am2, am3) is


equation of normal is given by y – y1 = m(normal)(x – x1)


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