Q11 of 33 Page 6

Find the equation of the normal to curve x2 = 4y which passes through the point (1, 2). (CBSE 2013)

It is given that curve is y2 = 4x.

Differentiating with respect to x, we get,





Now, the slope of the normal at point (1,2) is


Therefore, Equation of the normal at (1,2) is y - 2 = - 1(x – 1)


⇒ y - 2 = - x + 1


⇒ x + y - 3 = 0

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