Q16 of 33 Page 6

Find the equation of the tangent and the normal to the following curves at the indicated points:

at   (CBSE 2014)

finding slope of the tangent by differentiating the curve





normal is perpendicular to tangent so, m1m2 = – 1



equation of tangent is given by y – y1 = m(tangent)(x – x1)



equation of normal is given by y – y1 = m(normal)(x – x1)


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