Evaluate: 
[CBSE 2011]
Let I = 
This can be solved by applying method of substitution:
Let, x = sin θ
∴ θ = sin-1 x …(1)
As, x = sin θ
⇒ dx = cos θ dθ
∴ I = 
{∵ 1 – sin2θ = cos2 θ }
⇒ I = 
∴ I = sin-1 x + C {using equation 1}
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(CBSE 2011)
[CBSE 2012]
